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angelito
Honorable
Undefeatable Hero
proud father of a princess
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posted October 21, 2003 10:15 PM |
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@ delfontes
cool solution for riddle number 4 
-the original solution was :
1 foot + 1 foot + 1 foot = 1 yard (!)
Ok, I see that riddle number 5 is quite solved now, so I will go and find some more riddles for you 
@ SevenSeasJim
Riddle Nr.1 is the letter "e"
For the second riddle i have to say, that my english isnīt that good to find a solution for that 
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 21, 2003 10:22 PM |
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haha, not from the US, yet you use a riddle that has a non-metric distance conversion as the answer?
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angelito
Honorable
Undefeatable Hero
proud father of a princess
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posted October 21, 2003 11:00 PM |
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OK, donīt panic, here are the next ones: (the really hard ones will follow afterwards )
1. What's so peculiar about this sentence?
I do not know where family doctors acquired illegibly perplexing handwriting; nevertheless, extraordinary pharmaceutical intellectuality, counterbalancing indecipherability, transcendentalizes intercommunications' incomprehensibleness. (DL 2)
2. What's so special about the following sentence?
A big cuddly dog emitted fierce growls, happily ignoring joyful kids licking minute nuts on pretty queer rotten smelly toadstools underneath vampires who x-rayed young zombies. (DL 2)
3. In a stable there are men and horses. In all, there are 22 heads and 72 feet. How many men and how many horses are in the stable? (DL 2)
4. What english word has three consecutive double letters? (DL 4)
5. What word doesn't belong in this group?
that, hat, what, mat, cat, sat, pat, chat (DL 3)
And for "delfontes" problem with the non-metric solution: Donīt forget, that this is an international board and iīm not american, so some riddles will contain a bit of european flawer. *smile*
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 21, 2003 11:08 PM |
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Quote:
1. What's so peculiar about this sentence?
I do not know where family doctors acquired illegibly perplexing handwriting; nevertheless, extraordinary pharmaceutical intellectuality, counterbalancing indecipherability, transcendentalizes intercommunications' incomprehensibleness. (DL 2)
I'd have to count, but doesn't it appear that each word gets 1 letter longer than the previous one?
Quote:
2. What's so special about the following sentence?
A big cuddly dog emitted fierce growls, happily ignoring joyful kids licking minute nuts on pretty queer rotten smelly toadstools underneath vampires who x-rayed young zombies. (DL 2)
Any 5 year old can tell you this one , and proudly sing the answer I'm sure.
Quote:
3. In a stable there are men and horses. In all, there are 22 heads and 72 feet. How many men and how many horses are in the stable? (DL 2)
Ah-ha! An easier math question, hmmm. If all were horses, there would be 88 feet right? So there would be 16 feet extra. To cut out those feet, I'd imagine 8 would need to be people. 14 horses, 8 people. Checking my math 14x4=56 + 16 = 72
Quote:
4. What english word has three consecutive double letters? (DL 4)
Got me there, I'll have to think about it and get back to you, after someone else gets the answer.
Quote:
5. What word doesn't belong in this group?
that, hat, what, mat, cat, sat, pat, chat (DL 3)
I'd guess "what", the other words all have an "at" sound, it doesn't rhyme.
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angelito
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posted October 21, 2003 11:20 PM |
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Well, i think i really have to place the harder ones for you here...hehehe
All riddles are solved correctly, but the only harder one (DL 4) was not solved yet.
OK, I give you some minutes to find a solution. When i come back, I will bring some riddles and, believe me, there will appear many drops of sweat on your forehead
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Vadskye91
Promising
Supreme Hero
Back again
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posted October 21, 2003 11:44 PM |
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The answer to #4 is bookkeeper!
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Knowledge is power...
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 21, 2003 11:52 PM |
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Wow, great there . That I would have never guessed without looking up the answer. The word questions are beyond me, I'll have to cheat every time.
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Shadowcaster
Honorable
Supreme Hero
Shaded Scribe
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posted October 22, 2003 12:00 AM |
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No one has gotten this one, Delfontes...
...and you seem to be good at riddles, let's see if you can.
I'm by nature solitary, scarred by iron
and wounded by sword, weary of battle.
I often see the face of war, and fight
hateful enemies; yet I hold no hope
of help being brought to me in battle
Before I'm cut to pieces and perish.
At the city wall sharp-edged swords,
skillfully forged in the flame by smiths,
bite deeply into me. I must await
a more fearsome encounter; it is not for me
to find a physician on the battlefield,
one of those who heals wounds with herbs.
My sword wounds gape wider and wider;
death blows are dealt me by day and by night.
What am I?
____________
>_>
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Wolfman
Responsible
Supreme Hero
Insomniac
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posted October 22, 2003 12:04 AM |
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 22, 2003 12:12 AM |
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Quote:
I'm by nature solitary, scarred by iron
and wounded by sword, weary of battle.
I often see the face of war, and fight
hateful enemies; yet I hold no hope
of help being brought to me in battle
Before I'm cut to pieces and perish.
At the city wall sharp-edged swords,
skillfully forged in the flame by smiths,
bite deeply into me. I must await
a more fearsome encounter; it is not for me
to find a physician on the battlefield,
one of those who heals wounds with herbs.
My sword wounds gape wider and wider;
death blows are dealt me by day and by night.
What am I?
Wow, that one I don't think I know...
A tree comes to mind, but doesn't seem to fit at first to all the categories. I picture a city encroaching on the forest, and the tree interpreting it as a battle. The sharp edged swords could also be axes, but why wouldn't the riddle just say axes? Also a tree isn't solitary.
A shield might also work, as they certainly see more battles in a literal sense... but a death blow, by day, or by night, would surely break a shield (and who fights epic battles at night). Heck, a shield in a battle is definately not solitary either, as there are likely hundreds of them around.
Both could be cut to pieces and perish...
So I give up, maybe others will find it?
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angelito
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proud father of a princess
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posted October 22, 2003 01:09 AM |
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Very good Vadskye91!
Now here are the next challengers for you:
1. A rich Arabian died and in his last will says that :
"I have 17 camels and 3 sons. I want my oldest son to get the half of my camels, the 2nd oldest son has to get 1/3 of all the camels and the youngest on 1/9 of all the camels."
How could they find a solution for this problem? (DL 4)
2. You have a set of cards, which is no more complete (normaly it has 52 cards).
If you split them up equaly on 9 persons, there will remain 2 cards.
If you split them up equaly on 4 persons, 3 cards will remain.
If you split them up equaly on 7 persons, 5 cards will remain.
How many cards are in the set? (DL 3)
3. Lunch-time in a big family. Around the table, there are sitting 1 grandpa, 1 grandma, 2 fathers, 2 mothers, 4 children, 3 grandsons, 1 brother, 2 sisters, 2 sons, 2 daughters, 1 father-in-law, 1 mother-in-law and 1 daughter-in-law.
How many plates do you need at least? (DL 4)
4. Imagine there is a fictitious dog running from city A to city B. The distance between this 2 cities is 500 km. On one of his legs a tin has been fixed. The dog makes steps from a length of 1 meter and on every step, the tin bumps on the ground. His starting speed is 1 meter per second (1 m/s).
Everytime when he is hearing the tin bumping on the ground, he doubles his speed!
What is his speed, when he reaches city B ? (DL 5)
5. A peasant has 1000 dollars. He wants to buy 100 animals.
A pig costs 100$, a chicken 30$ and a chick 5$.
How many pigs, chicken and chicks has he got to buy to have exactly 100 animals? (DL 3)
Now letīs see, if these ones are that easy like the others before.....
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Shadowcaster
Honorable
Supreme Hero
Shaded Scribe
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posted October 22, 2003 01:42 AM |
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2. You have a set of cards, which is no more complete (normaly it has 52 cards).
If you split them up equaly on 9 persons, there will remain 2 cards.
If you split them up equaly on 4 persons, 3 cards will remain.
If you split them up equaly on 7 persons, 5 cards will remain.
How many cards are in the set? (DL 3)
47
3. Lunch-time in a big family. Around the table, there are sitting 1 grandpa, 1 grandma, 2 fathers, 2 mothers, 4 children, 3 grandsons, 1 brother, 2 sisters, 2 sons, 2 daughters, 1 father-in-law, 1 mother-in-law and 1 daughter-in-law.
How many plates do you need at least? (DL 4)
Seven?
4. Imagine there is a fictitious dog running from city A to city B. The distance between this 2 cities is 500 km. On one of his legs a tin has been fixed. The dog makes steps from a length of 1 meter and on every step, the tin bumps on the ground. His starting speed is 1 meter per second (1 m/s).
Everytime when he is hearing the tin bumping on the ground, he doubles his speed!
What is his speed, when he reaches city B ? (DL 5)
2^500 m/s(not sure about that one)
____________
>_>
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angelito
Honorable
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proud father of a princess
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posted October 22, 2003 01:46 AM |
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Good work shadowchaser,
riddle 2 and 3 are correctly solved.
But riddle number 4 is wrong. Do you really think i will give a difficulty level 5 (DL 5) if the solution is that easy?
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 22, 2003 01:59 AM |
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Quote:
4. Imagine there is a fictitious dog running from city A to city B. The distance between this 2 cities is 500 km. On one of his legs a tin has been fixed. The dog makes steps from a length of 1 meter and on every step, the tin bumps on the ground. His starting speed is 1 meter per second (1 m/s).
Everytime when he is hearing the tin bumping on the ground, he doubles his speed!
What is his speed, when he reaches city B ? (DL 5)
First step is to do the simple conversion, it is 500,000 meters between the two cities.
Now we just have to figure out when he'd get there if he is going at 1-2-4 etc.
Not knowing complex equasions very well I'll do it the hard way.
1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384,32768,65536,131072,262144,
At that point it will have made the journey .
I guess the answer then is 262144. Which incidentially is 19 seconds into the trip.
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angelito
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proud father of a princess
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posted October 22, 2003 02:06 AM |
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Quote:
First step is to do the simple conversion, it is 500,000 meters between the two cities.
Now we just have to figure out when he'd get there if he is going at 1-2-4 etc.
Not knowing complex equasions very well I'll do it the hard way.
1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384,32768,65536,131072,262144,
At that point it will have made the journey .
I guess the answer then is 262144. Which incidentially is 19 seconds into the trip.
Like i mentioned in my post above, if it would be that simple i wouldnīt gave it a (DL 5)
Both of you forget something in your way of thinking, or perhaps you didnīt read the riddle exactly.
......I like that, now Iīve found some harder riddles I think....yeahh baby, cīmon and get me...hehehe
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 22, 2003 02:21 AM |
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Unless you're saying that once he broke the speed of sound he'd no longer speed up, I don't see how that answer was incorrect.
If he did double his speed every step, that is how fast he would be going (assuming he started at point A)
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angelito
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proud father of a princess
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posted October 22, 2003 03:20 AM |
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ok delfontes, I will give you a hint, īcause youīre doing hard work...hehehe
Is there anything, that will come in your mind,
when I say "333m/s" ??
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delfontes
Known Hero
Sorcerer Extraordinaire
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posted October 22, 2003 03:26 AM |
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Nope, like I said, I don't know equasions.
333 meters per second, all I can do is convert that to KM per hour, which does nothing, hehehe
I'll check the board in a few days, someone will have answered it
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Shadowcaster
Honorable
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Shaded Scribe
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posted October 22, 2003 04:43 AM |
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angelito
Honorable
Undefeatable Hero
proud father of a princess
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posted October 22, 2003 04:51 AM |
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Quote:
255 m/s?
Thatīs wrong, but how do you get to this solution?
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