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gnollking
Supreme Hero
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posted September 27, 2009 04:13 PM |
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I don't know if someone has already posted this, but I bet that you cannot solve this:
3 men go to a restaurant and each one of them orders a pizza.
The men pay 6 euros for their pizzas, (so it's 3x6 = 18 euros)
The waiter takes the money and counts it. There are 5 euros too much. The real cost of the pizzas would have been 13 euros.
The waiter doesn't know how to give the 5 euros to 3 men, so he gives each man 1 euro, and keeps 2 euros for himself.
So, each man paid 5 euros (not 6, because they each got one euro back), and the waiter has 2 euros.
5€ x 3 = 15€
The waiter has 2€
2€ + 15€ = 17€
At the beginning each man paid 6€, which is (3x6 =) 18€
At the end there are only 17€
Where did the 1 euro disappear? 
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ohforfsake
Promising
Legendary Hero
Initiate
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posted September 27, 2009 04:47 PM |
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Quote:
I don't know if someone has already posted this, but I bet that you cannot solve this:
3 men go to a restaurant and each one of them orders a pizza.
The men pay 6 euros for their pizzas, (so it's 3x6 = 18 euros)
The waiter takes the money and counts it. There are 5 euros too much. The real cost of the pizzas would have been 13 euros.
The waiter doesn't know how to give the 5 euros to 3 men, so he gives each man 1 euro, and keeps 2 euros for himself.
So, each man paid 5 euros (not 6, because they each got one euro back), and the waiter has 2 euros.
5€ x 3 = 15€
The waiter has 2€
2€ + 15€ = 17€
At the beginning each man paid 6€, which is (3x6 =) 18€
At the end there are only 17€
Where did the 1 euro disappear?
I can't see anythig have dissapeared, they didn't pay 18 euros, they paid 15 euros. The pizza costed 13 euros, so out of those 15 euros 2 went to the waiter and 13 to the pizza.
Of the 18 euros to begin with, they get 3 back, 15 + 3 = 18 still.
Likewise does 13 (pizza) + 2 (waiter) + 3 (refund) = 18 (what they paid).
I don't know why you add waiter a second time in stead of refund. 
(You did (waiter (2) + pizza (13)) 15 + (waiter) 2 = total cash) for some reason).
So it should be:
5€ x 3 = 15€
They got 3€ back
3€ + 15€ = 18€
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TheDeath
Responsible
Undefeatable Hero
with serious business
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posted September 27, 2009 04:54 PM |
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The waiter has 18 euros after the paid, when he gives them 3 euros (1 for each) he is left with 15. He doesn't have "2" "extra" euros, he has 15, and the guys are left with 3+whatever they have in their pockets.
18-13 = 5
The waiter gives 3 to the men, and the "2" extra he doesn't "give to himself", he is left with 15 actually, not 13.
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gnollking
Supreme Hero
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posted September 27, 2009 06:55 PM |
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Carcity
Supreme Hero
Blind Sage
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posted September 27, 2009 07:37 PM |
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this one is probably easy to you guys buut anyway:
make it simpler:
3(3x+2)-2(x+2)
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Why can't you save anybody?
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smvuy
Known Hero
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posted September 27, 2009 09:16 PM |
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tell me the numbre that fullfills this x.x=x+1 (dont calculate, guess)
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baklava
Honorable
Legendary Hero
Mostly harmless
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posted September 27, 2009 09:31 PM |
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Do you mean x.x or x.xxxxxx...?
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"Let me tell you what the blues
is. When you ain't got no
money,
you got the blues."
Howlin Wolf
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smvuy
Known Hero
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posted September 28, 2009 06:13 PM |
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Quote:
Do you mean x.x or x.xxxxxx...?
x.x= the number "x" multiplied by tself
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TheDeath
Responsible
Undefeatable Hero
with serious business
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posted September 28, 2009 06:14 PM |
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lol and I thought it meant decimal point. Multiplication is represented by *, not a dot.
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zamfir
Promising
Supreme Hero
Allez allez allez
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posted September 28, 2009 06:59 PM |
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That's a banal second degree ecuation. Where's the fun in solving it?
Ok, x=(1-sqrt(5))/2 or (1+sqrt(5))/2 (both are solutions)
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5 Times TV
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ihor
Supreme Hero
Accidental Hero
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posted September 28, 2009 09:24 PM |
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The fun was to guess. Ha ha ha.
Quote:
(dont calculate, guess)
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Warmonger
Promising
Legendary Hero
fallen artist
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posted September 28, 2009 09:33 PM |
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You mean the golden proportion? Well, it's rather unlikely to 'guess' such a value, but it can be easily noticed when you know it.
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The future of Heroes 3 is here!
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smvuy
Known Hero
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posted September 28, 2009 10:44 PM |
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Quote:
You mean the golden proportion? Well, it's rather unlikely to 'guess' such a value, but it can be easily noticed when you know it.
I had that in mind 
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ohforfsake
Promising
Legendary Hero
Initiate
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posted October 01, 2009 04:55 PM |
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If it's 0 degree Celcius outside and suddenly it becomes double as cold, what's the temperature then?
(Note how cold it is, is a measure of the kinetic energy of the molecules).
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ihor
Supreme Hero
Accidental Hero
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posted October 01, 2009 05:16 PM |
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Edited by ihor at 17:19, 01 Oct 2009.
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As I remember kinetic energy is proportional to the absolute temperature. (I began to forgot school program of physics. )
0 deg Celsius = 273 deg Kelvin(spelling?)
273 / 2 = 136.5 deg Kelvin(approximately).
Answer: -136.5 deg Celsius.
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TheDeath
Responsible
Undefeatable Hero
with serious business
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posted October 01, 2009 05:20 PM |
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Edited by TheDeath at 17:20, 01 Oct 2009.
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Nevermind, I just realized it's division not subtraction (lol, the -Celsius confused me).
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ohforfsake
Promising
Legendary Hero
Initiate
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posted October 01, 2009 07:33 PM |
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Quote:
As I remember kinetic energy is proportional to the absolute temperature. (I began to forgot school program of physics. )
0 deg Celsius = 273 deg Kelvin(spelling?)
273 / 2 = 136.5 deg Kelvin(approximately).
Answer: -136.5 deg Celsius.
Yes I believe that's the correct answer. Would you've been able to solve it, if I hadn't told you what I meant by the term "cold"?
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ihor
Supreme Hero
Accidental Hero
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posted October 02, 2009 07:58 AM |
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Couldn't know that, but that was valuable hint.
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ohforfsake
Promising
Legendary Hero
Initiate
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posted October 10, 2009 08:55 PM |
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Okay I have a new one, I think many of you will like this, but you've to be very convincing in your arguments, as I'm not entirely certain about the answer myself. (Iirc it was something like 55/45 in favor of the Wraith, but I may very well be wrong). Anyway, here goes:
1 Vampire Lords battles 1 Wraith. No stat bonuses from a hero, etc.
The only way the Vampire Lord can win (doing a maximum of 9 damage I believe) (at least that's what the game told me), is to inflict this maximum twice in a row, to beat the Wraith (18 hp), otherwise the Wraith will simply heal all its hp back, and it's back to begin with, where the Vamp Lord then have lost a bit of health (1-3 pr. attack iirc).
The Wraith can't win by simply pressing shield every round, because the Vamp Lords have no retaliation. They can force infinite many rounds however, if they wish, but likewise they can't choose to press shield given the Vamp Lords hit a maximum, because the Vamp Lords are going to wait each time, so they always can get 2 hits in, in a row, before the Wraith heals.
So the question is, what's the probability of the Wraith winning?
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ihor
Supreme Hero
Accidental Hero
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posted October 12, 2009 08:15 AM |
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I think we should take into consideration the difference between attack and defense. Assuming this is HOMM3 Vampire Lord 10att 10def, Wraith 7att 7def. Vampire Lord damage is 5-8. The question to all: Is it correct that vampire lord will do 6-9 damage with same probabilities? The same for the wraiths. I don't want to search algorithms of calculation of damage now. 
Can somebody say exactly which damage could do those creatures and with which exact probabilities?
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